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1500 Hz. There is no relative motion between source and observer so no Doppler effect.
2From Î»â²=Î»(1âusv) we find Î»â²Î»=1âusv=1â40340=0.89.
3From fâ²=f(v+u0v) we find fâ²=500Ã(340+40340)=559Â Hz.
